$\lim_{x\to1}\left(\frac{ln\left(2-x\right)^2}{x-1}\right)$
$\int_0^{\infty}\left(\frac{e^{-t}}{1+e^{2t}}\right)dt$
$\lim_{x\to-1}\left(\frac{1-9x^2}{1-3x}\right)$
$400+120xyz+9$
$x2+6x+5+x+1$
$\frac{1}{64}n^3-27$
$\frac{3x}{2}+8=-7$
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