$-5+-f$
$\frac{1}{2}x^{2\:}+3x=36$
$\left|28-\left(-13\right)\right|$
$-10\:p\left(9\:-\:9\:p\right)$
$4x^2+12x+25$
$\lim_{x\to0}\left(\frac{ln\left(1+3x\right)}{x}\right)$
$4x+6<x$
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