$7\sqrt[5]{3}-3\sqrt[5]{3}-4\sqrt[5]{3}$
$\lim_{x\to1}\left(\frac{x^2+x-2}{x^2-4x+4}\right)$
$\frac{120}{4}$
$\left(3a^3+8b^4\right)^4$
$\frac{1}{x-4}+\frac{2}{x-2}=\frac{2x-3}{x^2-6x+8}$
$-1\left(2-2m^2\right)$
$\left(6x^4-7y^5\right)^2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!