$\frac{1}{x}+3<-4$
$\frac{d}{dx}\frac{x^2-4}{x+3}=y$
$\sqrt{9-4\left(4\right)\left(-2\right)}$
$2x^2+9x+12$
$13.8b-2.2+9.6+10.8b-b$
$2x\:+\:3\:-\:5x\:+\:10\:-\:6\:+\:x$
$\frac{x^4+x^2+2}{x-2}$
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