$\frac{1-cos\theta\:}{1+cos\theta\:}=\left(csc\theta\:-cot\theta\:\right)^2$
$\left(z+x-2\right)^3\left(x^2-4x\right)$
$\frac{1-x^9}{1-x^3}$
$\left(-8\right)\cdot3+10$
$\left(\frac{x+5}{x^2+2}\right)^3$
$-49x-xy^2-14xy$
$2>b+4$
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