$\left(6x+7\right)^2-4\left(3x-\frac{1}{2}\right)^2$
$\frac{dy}{dx}=\frac{e^{\left(y-10x\right)}}{5}$
$4x^2+4x-63$
$\lim_{x\to\infty}\left(\frac{1}{6tan\left(\frac{2x}{3}\right)}\right)$
$y=\left(10x+2\right)^x$
$\left(2y-5x\right)^2$
$\:2cos\:x\:+\:cos\:2x\:=\:-1,5$
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