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Find the break even points of the expression $2200x^2+\frac{2606083}{40}x+\frac{472083}{5}=0$

Step-by-step Solution

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Final Answer

$x=\frac{65152.075+\sqrt{65152.075^2-830866080}}{4400},\:x=\frac{65152.075-\sqrt{65152.075^2-830866080}}{4400}$
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Step-by-step Solution

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Divide $2606083$ by $40$

$2200x^2+65152.075x+\frac{472083}{5}=0$

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$2200x^2+65152.075x+\frac{472083}{5}=0$

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Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression 2200x^2+2606083/40x472083/5=0. Divide 2606083 by 40. Divide 472083 by 5. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=2200, b=65152.075 and c=94416.6. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying.

Final Answer

$x=\frac{65152.075+\sqrt{65152.075^2-830866080}}{4400},\:x=\frac{65152.075-\sqrt{65152.075^2-830866080}}{4400}$

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Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formula (general formula)Find the discriminant

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Function Plot

Plotting: $2200x^2+\frac{2606083}{40}x+\frac{472083}{5}$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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