$-4x^2-16x$
$\frac{dy}{dx}=\frac{xtan\left(6y^2-4\right)}{y\left(3x^2+1\right)}$
$y=x\:lnx^2$
$5secx-3=0$
$\frac{3}{2}-\frac{5}{4}x>\frac{7}{4}-\frac{2}{3}x$
$-3\:x\:-2\:x\:-1$
$\int-\frac{2}{5}e^{3-2x}dx$
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