$2x^3+3x^2-2x-x$
$-4a=48$
$\left(-6\right)^{17}$
$9c^2-40c+16$
$\frac{x^2+3x}{x^2+5x}$
$\frac{\left(x^2\right)^2}{4^3}$
$\frac{12y^{9}}{\left(3y^{2}\right)^{5}}$
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