$\frac{dy}{dx}=\frac{xe^{4x+y^5}}{y^4}$
$0-34z^4$
$x^2=8-2x$
$\int\:\left(x+3\right)^2dx$
$\int_0^12x^4e^{4x}dx$
$\left(2x+2\right)\left(x^2+3\right)$
$\int\left(\sqrt{x}+\frac{8}{\sqrt{x}}\right)^2dx$
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