$2x\le7x-35-5a$
$\ln\:2-\ln\:\left(3x+4\right)+\ln\:\left(4-3x\right)=\ln\:\:2$
$5n^2-20n+6=0$
$5m^2+15m^8$
$-9+-68+-17+8+-44$
$\frac{x}{3}=\frac{7x}{12x-15}$
$4^3\:\cdot16$
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