$\left(n-1\right)\left(n^3\right)\left(n+3\right)$
$-7=v-7$
$\int\:\frac{\left(3x^2+11x+2\right)}{\left(x+3\right)\left(x^2+1\right)}dx$
$\frac{x-1}{x+1}>1$
$3x^2-18x-15=0$
$\frac{3m^{x-1}}{m^3}-\frac{2m^{x-1}}{m^3}$
$\frac{2}{1-\sin^2x}$
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