$y=\ln\left(3x+6\right)^{2}$
$-3x+1<2x$
$\left(-15\right)\cdot\left(17\right)\cdot\left(36\right)\cdot\left(-1\right)$
$-19-2\cdot\left(-2\right)$
$\frac{\sqrt[3]{x^2}}{\sqrt[3]{x^2}}$
$7a-3a^2+2a^2$
$\left(5x^2+3x=2\right)$
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