$\left(2ab+b\right)^2$
$-2\left(m-2\right)=6$
$\left(a-b\right)\left(3a^2+b\right)$
$x^2-2x=1$
$x^2-22x-75=0$
$\int\frac{\sec3\left(x\right)\tan\left(x\right)}{1+\tan^2\left(x\right)}dx$
$4a^2a^2-3-a^2+3$
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