$\lim_{x\to0}\left(\frac{\sqrt[n]{1+x}-1}{x}\right)$
$\frac{x^2-3x+2}{2x+4}$
$\frac{14x+7}{x^2+x-6}$
$x'=\frac{8x}{t^2-16}$
$3x^6-\frac{2}{3}\sqrt{3x^3}a+\frac{a^2}{9}$
$\sec\left(a\right)=-5$
$\sqrt[3]{\frac{x^5-x^3+3}{x^2}}$
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