$\left(y-4\right)^2\:=\:12\left(x-6\right)$
$1x^2+\:1x+16$
$5x'+7x=0$
$\frac{x^2-7x+5}{x-5}$
$\cos^2\left(x\right)+\frac{\sin^2\left(x\right)\cos\left(x\right)}{\cos\left(x\right)}$
$18y+16+\frac{13}{\left(6y+1\right)}$
$\left(a^2-6\right)\left(a^2+4\right)$
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