$\lim_{x\to\infty}\left(\frac{3\sqrt{x}}{4\sqrt{x+1}}\right)$
$4x^2-8x=0\:$
$sin\left(10x\right)cos\left(6x\right)$
$y=\frac{x-5}{x^2-25}$
$6x^2+11r-10=0$
$\frac{dy}{dx}=\frac{\left(2xy\right)}{\left(x^2-2\right)\left(x^2+3\right)}$
$8x^3-9y^3+6xy-12x^2y\cdot2x+3y$
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