$\frac{6^{-3}}{6^{-4}}$
$3x^4+e^{4xy}=49$
$2.2\left(4.7+1.5y\right)-3.4\left(5x-2.7y\right)-\left(6.2x-7y\right)$
$\left(3a^3-5a\:b^2\:-6a^2\:b^3\right)$
$z\:+\:z^{\:-\:1}\:=5$
$2x:x^2$
$\left(x-7\right)^2=0$
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