$\left(-5\right)^4\left(-5\right)^3$
$x^4+4x^{-1}+\frac{4}{x^5}$
$x^2-6x\ge-8$
$\lim_{x\to0}\left(\frac{in\left(x+1\right)}{x}\right)$
$\int_0^{\infty}\left(\frac{4}{\left(16+x\right)\sqrt{x}}\right)dx$
$\sqrt[3]{-64x^9y^2}$
$4x^2-24x-4=81$
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