$y^2dy-3x^5dx=0$
$4-\left(-13\right)$
$-81+4a^{10}$
$2\left(1\right)-\left(-17\right)$
$\frac { 1 } { ( 2 x y + y ) }$
$\frac{x}{1+x^2}\le\frac{1}{2}$
$\ln\left(\frac{dy}{dx}\right)=\frac{x^2}{2}$
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