$\frac{d^2y}{dx^2}=-3$
$\frac{d^3}{dx^3}\left(e^{\sin\left(x\right)}\right)$
$\frac{x^3+4x+3}{x+3}$
$6\cdot y^2-3\cdot\sqrt{2}=18$
$2x^{2}-5x+7y-9=0$
$\int\frac{\sec^{3}x}{\tan^{4}x}dx$
$\left(8x^3-4x^6\right)^2$
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