$\frac{\left(3x+2\right)}{2}>\frac{4x-2}{5}$
$\frac{121m^8-n^2}{11m^4+n}$
$\:\:45x^2\:+\:20y^2\:-\:60xy$
$x^2+y^2-4x-6x-12=0$
$10\cdot7$
$y^3\sqrt{3}-y^2\:$
$3x^{3\:}+9xy^2=5x^3$
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