$\lim_{x\to-4}\left(\frac{x^4+64x}{x^2-16}\right)$
$\left(-1\right)-\left(-1\right)-\left(-1\right)+1$
$\frac{dy}{dx}=\frac{\left(sin\:\left(x\right)-2y\right)}{x}$
$6x^2+7x-24$
$\left(5x^2+2\right)\left(x+3\right)$
$\left(-15\right)+\left(6.3\right)$
$3csc^2x-4=0$
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