$\left(m^3-8\right)\left(m^3+12\right)$
$\frac{x^3+2x^2+4x+5}{x^2+4}$
$\frac{dy}{dx}=y\tan\left(x\right)+\sin\left(2x\right)$
$f\left(x\right)=\frac{1}{\sqrt{t}^2}+3t$
$x^2+x-20<x^2+6x+6$
$\frac{x+2}{7}\ge3$
$tan2\left(x\right)=-2.85$
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