$x^2+8x=15$
$\int\left(\left(x^2+8x+4\right)^5\left(2x+8\right)\right)dx$
$\lim_{x\to0}\left(\frac{-\cos\left(x\right)}{3x^2}\right)$
$64z^2-112z+49$
$\frac{x^5}{x^2-9}$
$\frac{dy}{dx}=\sec^2x$
$\sqrt[3]{3x^5}+\sqrt{4}$
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