$x^3-x^2=2x+y$
$\lim_{x\to0}\cos\left(\frac{\pi}{x}\right)$
$\int_0^{\frac{1}{4}}\left(\frac{1}{\sqrt{1-16x^2}}\right)dx$
$\:\frac{-56}{8}$
$\left(10x^2+5y^n\right)^3$
$\frac{e^{-3x}\left(2x-5\right)^1\frac{1}{2}}{\left(6-5x\right)^4}$
$6.84+0.28\cdot0.8$
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