$\left(5a+6m+3\right)^2$
$\lim_{x\to2}\left(\frac{x^2+4x+4}{x^2-4}\right)$
$\left(x^3-3x^2-4x+12\right)$
$\left(3ab^2+7mn\right)^3$
$6x^2+24xy^2+16y^4$
$n^2-17=-2n$
$\frac{d}{dx}.5x^2+2y^2=1$
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