$\frac{d}{dx}\sqrt[3]{1-6x}$
$2x^3-3y^2+2,\:x=0,\:y=1$
$\frac{x^2}{7-x}$
$-\frac{1}{3}\:.\:3$
$3y^2y'-x^3=0$
$\int_0^{\infty}\frac{49\cdot\cos\left(x\right)}{-40\cdot x}dx$
$7x-2\left(x-5\right)=3\left(x+2\right)+2\left(x+2\right)$
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