$3x-5<20$
$3x+69=180$
$\lim_{x\to\infty}\left(\frac{x\cdot\left(x+2\right)}{x^2+2x+2}\right)$
$\left(-10+5-9\right)-4-\left(-7+6\right)+2$
$-9\left(-3\right)^2$
$\left(xy\:+\:x\right)\left(xy\:-\:x\right)$
$-3x^2+8x+24$
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