$3x-x^3+4x+5+x^3+4x^2-6$
$20 = r + 11$
$-2x^4\cdot6x^3$
$\left(x+2\right)\frac{dy}{dx}+2y=3\left(x+2\right)^2$
$\frac{dy}{dx}=\frac{2xy}{y+1}$
$\left(2r-3s\right)^2$
$x+5>4$
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