$\int\frac{1}{9}x^3\cdot\:\sqrt{\left(\frac{1}{3}x+4\right)\:}\:\:dx$
$3\cdot1-4\cdot.5$
$2x-8>9x-10$
$553^0$
$\frac{1}{2}\:\left[-20\right]$
$\left(x+2\right)^2<x^2-5x+3$
$4x^2-20x+25=0$
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