$6-4x-13$
$x^2\cdot z''\left(x\right)-xy\cdot z''\left(y\right)=z-y$
$\cot^2x+\cot x$
$de\:20\:-\:\left(-\:5\:\right)\:$
$-2-x=10$
$\left(x+6\right)\left(x+3\right)+\left(x+10\right)\left(x-1\right)$
$\int\:\frac{x^2+x-8}{x^3-4x^2}\:dx$
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