$\lim_{y\to-5}\left(\left(3-y\right)\sqrt{y^2-9}\right)$
$4x^2=-3-8x$
$1r+3-6r+1r$
$\frac{7}{\frac{1}{6}}$
$-\left(2x-8\right)^2$
$x^2+6x=40$
$\left(-4z^2\right)+\left(+6yx\right)+\left(-10yx\right)+\left(20z\right)$
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