$\frac{\left(x-1\right)}{x^2-4}+\frac{1}{x-2}=\frac{\left(x+4\right)}{x+2}$
$-\left(3a\right)^0$
$\int\frac{-3x-5}{x^3+7x^2+12x}dx$
$2\left(\frac{x}{2}\right)\left(\frac{3y}{4}\right)$
$x\:=\:\log_{1.05}$
$-23x^2+68x+3=0$
$4x^2+12+60$
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