$3x^2y-2xy^2;\:x=-2;\:y=3$
$-2\left(-2\right)^{2-1}$
$\left(4x+3y\right)^2-\left(4x-3y\right)^2$
$\infty-4$
$\frac{9x^4}{16}-\frac{\left(9x^4-4\right)}{6x^2}-\frac{1}{9x^4}$
$\frac{x^3+2x^2+4x+2}{x^2-0}$
$\left(3x+2\right)^2+\left(3x+1\right)^2-3\left(2x+1\right)$
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