$\left(4a^3-3b^2\right)^3$
$\sqrt[3]{1.167}$
$0.085\cdot10$
$x\ln x^2+3$
$\left(x^3-x^2+x+1\right)^2$
$\left(2c^2+9\right)-\left(3c^2-7\right)$
$\frac{dy}{dx}=\left(x+2\right)\left(e^y\right)$
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