$\left(4m+1\right)^3$
$\sqrt{8m}+2\sqrt{24}-5\sqrt{18m}-5\sqrt{6m}$
$\lim_{x\to\infty}\left(\frac{2x}{x}\right)$
$\frac{3x^2-3x+1}{x-2}$
$3\:-\:1x\:+\:4$
$\frac{x^5-x^4+x^2-2}{x^2+1}07$
$d+0.38d$
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