$f^2+0.4f+0.04$
$\frac{4x^4-40x^2-5x+25}{x+3}$
$4-1.-3^2$
$2x\:-\:2\:+\:4\:$
$1^x^{+2x}$
$x-3\left(3x^2+7x-5\right)$
$3x^2-8x=11$
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