$8+3\left(5x+4\right)+7x$
$5x^3+15x^2+5$
$3x^2-5x+12;\:x=-2$
$\lim_{x\to0}\left(\frac{\sin\left(x\right)+3x}{x^2-4x}\right)$
$\int\left(x^2+2x-3\right)^2\left(2x+2\right)dx$
$9x-3y+5+-x-y+4+-5x+4y-9$
$\left(m-n\right)^2-6\left(m-n\right)+9$
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