$\frac{8}{s^3\left(s^2-s-2\right)}$
$2.36\cdot8$
$\lim_{x\to0}\left(\frac{\left(x^2\:-\:\sin\:^2\left(3x\right)\right)}{2x^2}\right)$
$\left(1\right)\left(-1\right)\left(3\right)$
$3x+9\ge12$
$\sqrt{-16}+\sqrt{-25}$
$\lim_{x\to-3}\left(\frac{x^2-8x-13}{x^2-5}\right)$
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