$\frac{25a}{5a}$
$\frac{m^3+8^3}{m+2}$
$\left(4a+2\right)\left(6a^2-a+2\right)$
$x^2+12>8x$
$\lim_{x\to\infty}\left(\frac{\left(-e\right)^x}{4}\right)$
$-6x+3y-5x+6y$
$cos^4x-sin^4x=1-2sin^2x$
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