$-\left(14-x\right)^2$
$6x-10=-16$
$f\left(x\right)=\frac{x^2-4}{x^2}$
$\int x\cdot\sec\left(6x^2\right)dx$
$4x-x^2-9$
$\sqrt{\frac{10}{x^3}}$
$\int\left(\frac{x^2-1}{\sqrt[3]{\left(x^3-3x+16\right)}}\right)dx$
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