$x-7\le5$
$2x^2+24$
$\left(10x^5-2\right)^2$
$\frac{dx}{dt}=\frac{7\left(1+x\right)}{1-x}$
$3x^2+6x-8\:\cdot\:-4x^2+8x-2$
$f\left(x\right)=\frac{\sqrt{x+1}}{x^5\left(x^2+1\right)}$
$\frac{6x+5x^2-2x^3+8}{x-6}$
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