$1\:+\:5\:+\:1\:-\:4\:-\:1\:-\:2\:$
$\frac{dy}{dx}=e^{4y+4x}$
$\left(\frac{a^{-4}b^2}{ba^2\cdot a^2b^{-4}}\right)^3$
$\left(y\right)\left(y-7\right)$
$m^2-3m-4=0$
$\int_0^1\left(\frac{1}{x^2+49}\right)dx$
$6x^4\:-\:14x^2$
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