$10h^3\left(4h\right)$
$137,27\:-16,298$
$\lim_{x\to2}\left(\frac{x^2+x-6}{x^3-x^2-8x+12}\right)$
$\lim_{x\to\infty}\left(\frac{4x-2}{4x-3}\right)^{4x^2-1}$
$\int\csc\left(v\right)dv$
$\frac{dy}{dx}\left(x^2+xy+y^3=1\right)$
$4x^3+6x^2$
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