$\int\frac{4s-10}{\left(s-3\right)\left(s-2\right)\left(s-1\right)}dx$
$\left(-8\right)-\left(-3\right)+4-\left(-15\right)$
$\left(2p-8\right)^2$
$2x^2-12x+16$
$-15+2+4-1$
$\frac{x^2-2x-3}{x^3-7x^2+15x-9};\:x=3$
$i^2\cdot\:r$
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