$\left(x^2\:+\:10x\right)\:\left(x^2\:-\:10x\right)$
$\frac{\left[2x-2\right]}{3}=\frac{\left[x+7\right]}{3}$
$10x^2-x-3$
$\left(\:4x+2y\right)^2$
$-9-4\cdot\left|12-\left(7-2\right)\right|+23$
$a^2+20-21a$
$\int\left(xtan^8\left(x^2\right)sec^2\left(x^2\right)\right)dx$
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