$-27=-8$
$-\left(1-3n\right)+6n$
$x-\sqrt{x-1}=1$
$\lim_{x\to\infty}\left(\frac{e^{2x}}{\left(ln\left(x\right)\right)^2}\right)$
$\infty\cdot\left(-2.16\right)$
$-8+2\:x\:5\:-1$
$\frac{\left(1-sinx\right)\left(1+sinx\right)}{cosx}\cdot secx$
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