$5\cdot37$
$\int\left(\frac{1}{\left(x^2+7x-6\right)}\right)dx$
$\frac{x}{\:8}=-3$
$\log4\left(4xy\right)^3$
$\left(x+5\right)\left(x-6\right)+3x-4\le\left(x+3\right)\left(x-6\right)+5$
$\left(6xyz-2yz\right)^3$
$-3+8\cdot\left(-2\right)+19-9\left(-2\right)$
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