$\:\left(3b+8c\right)\:\left(3b-4c\right)$
$\left(8+xy\right)^2$
$\lim_{x\to-13}\left(\frac{x-3}{\sqrt{x+13}-4}\right)$
$4x^2-8x+9$
$-284-602$
$cos\left(2x\right)-cos\left(4x\right)=sqrt\left(3\right)\:sen\left(3x\right)$
$15\tan^2a+14\tan a-8$
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